@[email protected]M to Science [email protected]English • 1 year agoMagic πmander.xyzimagemessage-square68fedilinkarrow-up1726
arrow-up1726imageMagic πmander.xyz@[email protected]M to Science [email protected]English • 1 year agomessage-square68fedilink
minus-square@[email protected]linkfedilinkEnglish27•1 year agoDiameter of a hydrogen atom is all well and good, but how many digits of pi will we need to be accurate to a Planck Length?
minus-square@[email protected]linkfedilinkEnglish19•1 year agoHonestly probably not that many more. My guess since I’m too lazy to do the math is less than 100.
minus-square@[email protected]linkfedilinkEnglish23•1 year agoThe diameter of a hydrogen atom is over 10,000,000,000,000,000,000,000,000 plank lengths. So based on this post I have no idea.
minus-square@[email protected]linkfedilinkEnglish19•edit-21 year agoWell that’s only 26 more digits, so we’re probably good at 100 digits of pi. [citation needed]
minus-square@[email protected]linkfedilinkEnglish15•1 year agolog_10(size of observable universe / planck length) = 61.74… so like 63 digits of precision for everything are enough
minus-squareMalgaslinkfedilinkEnglish5•1 year agoThe width of a hydrogen atom is 3.1*10^24 Planck lengths. So, yeah, 65 digits of pi ought to do it.
Diameter of a hydrogen atom is all well and good, but how many digits of pi will we need to be accurate to a Planck Length?
Honestly probably not that many more. My guess since I’m too lazy to do the math is less than 100.
The diameter of a hydrogen atom is over 10,000,000,000,000,000,000,000,000 plank lengths.
So based on this post I have no idea.
Well that’s only 26 more digits, so we’re probably good at 100 digits of pi. [citation needed]
log_10(size of observable universe / planck length) = 61.74… so like 63 digits of precision for everything are enough
The width of a hydrogen atom is 3.1*10^24 Planck lengths. So, yeah, 65 digits of pi ought to do it.