@[email protected]M to Science [email protected]English • 1 year agoMagic πmander.xyzimagemessage-square68fedilinkarrow-up1726
arrow-up1726imageMagic πmander.xyz@[email protected]M to Science [email protected]English • 1 year agomessage-square68fedilink
minus-square@[email protected]linkfedilinkEnglish19•1 year agoHonestly probably not that many more. My guess since I’m too lazy to do the math is less than 100.
minus-squareMalgaslinkfedilinkEnglish5•1 year agoThe width of a hydrogen atom is 3.1*10^24 Planck lengths. So, yeah, 65 digits of pi ought to do it.
minus-square@[email protected]linkfedilinkEnglish23•1 year agoThe diameter of a hydrogen atom is over 10,000,000,000,000,000,000,000,000 plank lengths. So based on this post I have no idea.
minus-square@[email protected]linkfedilinkEnglish19•edit-21 year agoWell that’s only 26 more digits, so we’re probably good at 100 digits of pi. [citation needed]
minus-square@[email protected]linkfedilinkEnglish15•1 year agolog_10(size of observable universe / planck length) = 61.74… so like 63 digits of precision for everything are enough
Honestly probably not that many more. My guess since I’m too lazy to do the math is less than 100.
The width of a hydrogen atom is 3.1*10^24 Planck lengths. So, yeah, 65 digits of pi ought to do it.
The diameter of a hydrogen atom is over 10,000,000,000,000,000,000,000,000 plank lengths.
So based on this post I have no idea.
Well that’s only 26 more digits, so we’re probably good at 100 digits of pi. [citation needed]
log_10(size of observable universe / planck length) = 61.74… so like 63 digits of precision for everything are enough